The planet earth orbits around the sun and also spins around its own axis. 33% part (a) calculate the angular momentum of the earth in its orbit around the sun in kg • m2/s

Answers

Answer 1
Answer: The angular momentum can be found by the formula:
L = m · v · r

Where:
m = mass of Earth = 5.972×10²⁴ kg
v = velocity of Earth around the Sun = 2.978×10⁴ m/s
r = distance from Sun = 1.496×10¹¹ m

Now, apply the formula:
L = 5.972×10²⁴ · 2.978×10⁴ · 1.496×10¹¹ 
   = 2.661
×10⁴⁰ kg·m²/s

The angular momentum of Earth in its motion around the Sun is 2.661×10⁴⁰ kg·m²/s.
Answer 2
Answer:

Is known:

m = Earth's mass = 5.972 × 10²⁴ kg

v = the speed of the Earth around the Sun = 2,978 × 10⁴ m / s

r = distance from the Sun = 1.496 × 10¹¹ m

Asked:

L?

Answer:

L = m · v · r

L = 5,972 × 10²⁴ · 2,978 × 10⁴ · 1,496 × 10¹¹

L = 2,661 × 10⁴⁰ kg · m² / s

So, the angular momentum of the Earth in its motion around the Sun is 2.661 × 10⁴⁰ kg · m² / s.

Further Explanation

In physics, momentum is a quantity related to the velocity and mass of an object. in classical mechanics, momentum (denoted by P) is defined as the product of mass and velocity, thus producing vectors.

The momentum of an object (P) having mass m and moving with velocity v is defined as:

P = mv

Mass is a scalar quantity, while velocity is a vector quantity. Multiplication of scalar quantities with vector quantities will produce vector quantities. So, momentum is a vector quantity. The momentum of a particle can be seen as a measure of the difficulty of settling an object. For example, a heavy truck has greater momentum than a light car that moves at the same speed. Greater force is needed to stop the truck compared to a lightweight car in a certain amount of time. (The magnitude of mv is sometimes expressed as linear momentum of the particle to distinguish it from angular momentum).

Speed ​​is a vector quantity that shows how fast an object is moving. The magnitude of this vector is named speed and is expressed in units of meters per second (m / s or ms − 1). The mass may be a property of an object that's accustomed to explain the varied behaviors of the item being monitored. In everyday use, mass is typically synonymous with weight. But in keeping with modern scientific understanding, the burden of an object is caused by the interaction of mass with the field

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Grade: College

Subject: Physics

keywords: momentum


Related Questions

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GUYS PLEASE HELP THIS IS DO IN LIKE 30 MIN!!!!!!Question 1 Which of the following color schemes (specifically in jewel tones) is on trend for 2020?

a all of the above

b complimentary

c analogous

d monochromatic


Question 2 Which of the following color pallettes is on trend for 2020?

a primary colors

b earth tones

c cool tones

d hues of pink


Question 3 Which of the following items could be painted in a dark color to be on trend in 2020?

a toilets

b doors

c ceilings

d baseboards


Question 4 Which of the following design genres is OUT in 2020?

a country chic

b traditional

c industrial

d bohemian


Question 5 When designing interiors for the elderly, which of the following items can be used to replace traditional door knobs?

a clap lights

b sliding glass doors

c pocket doors

d door levers


Question 6 What design adaptation can be implemented in the bathroom to help with elderly clients?

a walk in shower

b garden tub

c Jacuzzi

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Question 7 Which of the following floor types can aid in safe movement throughout the house?

a soft area rugs

b cork

c cement

d slick tile


Question 8 Where should cabinets be place in the kitchen as a safety measure for designing for the elderly?

a basic counter tops that are easily accessible

b above the refrigerator

c over long/extended cabinets

d over the stove

Answers

Answer:

1: a all of the above

2: b earth tones

3: b doors

4: c industrial

5: d door levers

6: a walk in shower

7: b cork

8: a basic counter tops that are easily accessible

Explanation:

I took the test and got 100%

Answer:

1) monochromatic

2) earth tones

3) doors

4) industrial

5) door levers

6) walk in shower

7) cork

8) a basic counter tops that are easily accessible

Explanation:

I took the test also

Assuming the same initial conditions as described in FNT 2.2.1-1, use the energy-interaction model in two different ways (parts (a) and (b) below) to determine the speed of the ball when it is 4 meters above the floor headed down: a) Construct a particular model of the entire physical process, with the initial time when the ball leaves Christine’s hand, and the final time when the ball is 4 meters above the floor headed down.
b) Divide the overall process into two physical processes by constructing two energy-system diagrams and applying energy conservation for each, one diagram for the interval corresponding to the ball traveling from Christine’s hand to the maximum height, and then one diagram corresponding to the interval for the ball traveling from the maximum height to 4 meters above the floor headed down.
c) Did you get different answers (in parts (a) and (b)) for the speed of the ball when it is 4 meters above the floor headed down?

Answers

Answer:

(a). Vf = 7.14 m/s

(b). Vf = 7.14 m/s

(c). same answer

Explanation:

for question (a), we would be applying conservation of energy principle.

but the initial height is h = 1.5 m

and the initial upward velocity of the ball is Vi =  10 m/s

Therefore

(a). using conservation law

Ef = Ei

where Ef = 1/2mVf² + mghf  ........................(1)

also Ei = 1/2mVi² + mghi  ........................(2)

equating both we have

1/2mVf² + mghf = 1/2mVi² + mghi

eliminating same terms gives,

Vf = √(Vi² + 2g (hi -hf))

Vf = √(10² + -2*9.8*2.5) = 7.14 m/s

Vf = 7.14 m/s

(b). Same process as done in previous;

Ef = Ei

but here the Ef = mghf ...........(3)

and Ei = 1/2mVi² + mghi ...........(4)

solving for the final height (hf) we relate both equation 3 and 4 to give

mghf = 1/2mVi² + mghi ..............(5)

canceling out same terms

hf = hi + Vi²/2g

hf = 1.5 + 10²/2*9.8 = 6.60204m ............(6)

recalling conservation energy,

Ef = Ei

1/2mVf² + mghf = mghi

inputting values of hf and hi we have

Vf = √(2g(hi -hf)) = 7.14 m/s

Vf = 7.14 m/s

(c). From answer in option a and c, we can see there were no changes in the answers.

A neutral metal ball is suspended by a string. A positively charged insulating rod is placed near the ball, which is observed to be attracted to the rod. This is because:____________. a. the ball becomes negatively charged by induction
b. the ball becomes positively charged by induction
c. the string is not a perfect insulator
d. there is a rearrangement of the electrons in the ball
e. the number of electrons in the ball is more than the number in the rod

Answers

Answer:

d. there is a rearrangement of the electrons in the ball

Explanation:

Inside the neutral metal ball, there are equal no. of positive charges (protons) and negative charges (electrons). Normally, the charges are distributed evenly throughout the ball.

However, when the positively charged insulating rod is brought near, since positive charges and negative charges attract each other, the electrons (-ve charges) in the metal ball moves towards the side nearest to the rod. The metal ball gets attracted to the rod.

a and b are not correct because the rod is insulating, so electrons cannot be transferred between them to induce a net charge in the metal ball. the no. of electrons is unrelated to the attraction between opposite charges , so e is incorrect as well.

A parallel-plate capacitor is charged and then disconnected from the battery. By what factor does the stored energy change when the plate separation is then doubled?

Answers

Answer:

U/U₀ = 2

(factor of 2 i.e U = 2U₀)

Therefore, the energy stored in the capacitor is doubled when the plate separation is doubled while the capacitor has been disconnected

Explanation:

Energy stored in a capacitor can be expressed as;

U = 0.5CV^2 = Q^2/2C

And

C = ε₀ A/d

Where

C = capacitance

V = potential difference

Q = charge

A = Area of plates

d = distance between plates

So

U = Q^2/2C = dQ^2/2ε₀ A

The initial energy of the capacitor at d = d₀ is

U₀ = Q^2/2C = d₀Q^2/2ε₀ A ....1

When the plate separation is increased after the capacitor has been disconnected, the charge Q of the capacitor remain constant.

The final energy stored in the capacitor at d = 2d₀ is

U = 2d₀Q^2/2ε₀ A ...2

The factor U/U₀ can be derived by substituting equation 1 and 2

U/U₀ = (2d₀Q^2/2ε₀ A)/( d₀Q^2/2ε₀ A )

Simplifying we have;

U/U₀ = 2

U = 2U₀

Therefore, the energy stored in the capacitor is doubled when the plate separation is doubled while the capacitor has been disconnected.

The elasticity of demand for gasoline has been estimated to be 2.0, and the standard error is 1.0. The upper and lower bounds on the 95 percent confidence interval for the elasticity of demand for gasoline are:

Answers

Answer:

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_(\alpha/2)(\sigma)/(√(n))   (1)  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_(\alpha/2)=1.96

The standard error for this case is given:

SE =(\sigma)/(√(n))=1

Now we have everything in order to replace into formula (1):

2-1.96*11=0.04    

2+1.96*1=3.96  

Explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X =2 represent the sample mean for the sample  

\mu population mean (variable of interest)  

s represent the sample standard deviation  

n represent the sample size  

Calculate the confidence interval

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_(\alpha/2)(\sigma)/(√(n))   (1)  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_(\alpha/2)=1.96

The standard error for this case is given:

SE =(\sigma)/(√(n))=1

Now we have everything in order to replace into formula (1):

2-1.96*11=0.04    

2+1.96*1=3.96  

24-gauge copper wire has a diameter of 0.51 mm. The speaker is located exactly 4.27 m away from the amplifier. What is the minimum resistance of the connecting speaker wire at 20°C? Hint: How many wires are required to connect a speaker!Compare the resistance of the wire to the resistance of the speaker (Rsp = 8 capital omega)

Answers

Answer:

 R = 8.94 10⁻² Ω/m,    R_sp / R_total = 44.8

Explanation:

The resistance of a metal cable is

         R = ρ L / A

The area of ​​a circle is

          A = π R²

The resistivity of copper is

        ρ = 1.71 10⁻⁸ ohm / m

Let's calculate

       R = 1.71 10⁻⁸  4.27 / (π (0.51 10⁻³)²)

       R = 8.94 10⁻² Ω/m

Each bugle needs two wire, phase and ground

The total wire resistance is

        R_total = 2 R

        R_total = 17.87 10⁻² Ω

Let's look for the relationship between the resistance of the bugle and the wire

      R_sp / R_total = 8 / 17.87 10⁻²

      R_sp / R_total = 44.8

Final answer:

The resistance of the speaker wire can be calculated using the formula for the resistance of a wire, taking into account the resistivity of copper, the length and thickness of the wire, and whether a single or pair of wires is used.

Explanation:

The question is asking you to find the minimum resistance of a copper wire given its diameter and length, plus the resistance of the speaker it's connected to. Resistance of a wire is calculated using the formula R=ρL/A, where R is the resistance, ρ (rho) is the resistivity of the material (in this case, copper), L is the length of the wire, and A is the cross-sectional area of the wire.

First, you need to find the area of the 0.51 mm diameter wire. The area (A) of a wire is given by the formula π(d/2)^2 where d is the diameter of the wire. After calculating the area, use the formula R=ρL/A to calculate the resistance. For copper wire at 20°C, ρ is approximately 1.68 × 10^-8 Ω·m. Substituting these values into the formula will give you the resistance of the wire in ohms.

Note: you may need to consider whether you have just a single wire or a pair, since two wires are typically required to connect a speaker. If a pair is used, each wire will carry half the current, which affects the total resistance.

Learn more about Electric Resistance here:

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