Which pair of numbers has the same gcf as that of 48 and 78A)4 and 34
B)8 and 18
C)9 and 15
D)12 and 30

Answers

Answer 1
Answer: greatest common factor is found by finding the factors of each
factors48=2 times 2 times 2 times 2 times 3
78=2 times 3 times 13
find common group
comon group=2 times 2=6
gcf=6
find others
narrow it down by crossing out any choices with numbers not divisible by 6
(crosses out A,B,C since A has 4 and B has 8 and C has 9)

therefor the answer is D, 12 and 18
check
12=2 times 2 times 3
18=2 times 3 times 3
common group=2 times 3=6
correct

answer is D, 12 and 18

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Find the quotient. (5x^4 - 3x^2 + 4) ÷ (x+1)​

Answers

Answer:

The first one: 5x^3 -5x^2 +2x -2 + 6/x+1

Step-by-step explanation:

Identify the correct ways to classify ∠1 and ∠4 in the figure shown below.

Answers

Answer:

adjacent and complementary angles

Step-by-step explanation:

we know that

If the sum of two angles is equal to 90\° then, the angles are Complementary

and

Two angles are Adjacent when they have a common side and a common vertex

In this problem we have

m<1+m<4=90\° -----> by complementary angles

and

m<1 and m<4 have a common side and a common vertex

therefore

m<1 and m<4 are adjacent and complementary angles

They are adjacent and complementary.
Next to each other and add up to 90 degrees.

What is 7/9 divided by 2 13/18

Answers

7/9 divided by 2 13/18 is 2/7
hoped this helps

Final answer:

To divide 7/9 by 2 13/18, convert the mixed number to an improper fraction, then multiply the fractions and simplify. The result is 42/141.

Explanation:

To divide 7/9 by 2 13/18, we need to convert the mixed number 2 13/18 into an improper fraction. To do this, we multiply the whole number (2) by the denominator of the fraction (18) and add the numerator (13). This gives us 47. So, 2 13/18 can be written as the improper fraction 47/18.

Now, we can divide 7/9 by 47/18. We multiply the first fraction by the reciprocal of the second fraction (flip the numerator and denominator). So, (7/9) ÷ (47/18) becomes (7/9) × (18/47).

To multiply fractions, we multiply the numerators together and the denominators together. This gives us (7/9) × (18/47) = (7 × 18) / (9 × 47) = 126/423.

Lastly, we can simplify the fraction by dividing the numerator and denominator by their greatest common divisor. The GCD of 126 and 423 is 3. Dividing both numerator and denominator by 3 gives us the simplified answer: 42/141.

Learn more about Dividing Fractions here:

brainly.com/question/1627825

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Two-ninths of the total number of batteries in Richard's desk drawer is madeup of 16 batteries. How many batteries are there in the drawer?

Answers

You are told 2/9 = 16

Let total number of batteries = x

So you now have 2/9x = 16

To find x divide both sides by 2/9

X = 72 total batteries

Awnser

72

i dunno how to explain i did it in my head

Solve with steps for this questions

Answers

Answer:

see explanation

Step-by-step explanation:

given

g(x) = 3x² - 5 then g(t) = 3t² - 5

Also g(t) = - (7)/(2) t, hence

3t² - 5 = - (7)/(2) t

multiply both sides by 2 to eliminate the fraction

6t² - 10 = - 7t ( add 7t to both sides )

6t² + 7t - 10 = 0 ← in standard form

(t + 2)(6t - 5) = 0 ← in factored form

Equate each factor to zero and solve for t

t + 2 = 0 ⇒ t = - 2

6t - 5 = 0 ⇒ t = (5)/(6)

7/2t. That’s my answer but sorry I didn’t work it out

in a first aid kit the ratio of large bandages to small bandages is 5 to 2. Based on this ratio, how many large bandages are in the kit if there are total of 60 bandages?

Answers

The best way to answer this question is to set up the first sentence as a ratio of large bandages to total bandages. You would write 5 large bandages to 7 total bandages to 7 total bandages.  Then you would make this equivalent to x number of large bandages to 60 total.  It would look like this 5:7 = x:60.  You could use cross products to multiply 60 by 5 to get 300.  7 times x also should equal 300.  Unfortunately, this example will not leave us with a whole number of bandages, but 300/7 is a repeating decimal or a mixed number (42 6/7 large bandages).