Which factor is likely to impact the possible number of compounds?
which factor is likely to impact the possible number of - 1

Answers

Answer 1
Answer:

Answer:

The correct answer is the tendency of all the elements to react with every other element.  

Explanation:

A component in which two or more elements are bonded chemically leads to the production of a compound. A compound refers to a pure component as it comprises elements that are in their pure state. The formation of a compound takes place when the elements react with each other based upon their reactivity.  

For example, the element chlorine is deficient of one electron and the element sodium exhibits one additional electron. Thus, chlorine easily reacts with the sodium in order to obtain stability. Therefore, the formation of sodium chloride takes place. Hence, it can be concluded that the tendency of all the elements to react with every other element is the condition, which is possible to influence the probable number of compounds.

Answer 2
Answer: the impact of possible number of compounds is the ability of all elements to react with every other atoms

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The combustion of 0.295 kg of propane produces 712 g of carbon dioxide. What is the percent yield of carbon dioxide? ( Make sure to balance equation) C3H8 (g)+ 029) à co2 g H200 0a. 124%
b. 41 .4%
c. 80.5%
d. 0.805 %

Answers

Answer:

Option C. 80.5%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Next, we shall determine the mass of C3H8 that reacted and the mass of CO2 produced from the balanced equation.

This is illustrated below:

Molar mass of C3H8 = (3x12) + (8x1) = 36 + 8 = 44 g/mol

Mass of C3H8 from the balanced equation = 1 x 44 = 44 g

Molar mass of CO2 = 12 + (2x16) = 12 + 32 = 44 g/mol

Mass of CO2 from the balanced equation = 3 x 44 = 132 g

From the balanced equation above,

44 g of C3H8 reacted to produce 132 g of CO2.

Next, we shall determine the theoretical yield of CO2.

This can be obtained as shown below:

From the balanced equation above,

44 g of C3H8 reacted to produce 132 g of CO2.

Therefore, 0.295 kg (i.e 295 g) will react to produce = (295 x 132)/44 = 885 g of CO2.

Therefore, the theoretical yield of CO2 is 885 g.

Finally, we shall determine the percentage yield of CO2 as follow:

Actual yield of CO2 = 712 g

Theoretical yield of CO2 = 885 g

Percentage yield of CO2 =..?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield of CO2 = 712/885 x 100

Percentage yield = 80.5%

Therefore, the percentage yield of CO2 is 80.5%.

Choose All correct statements about the crystal structure of materials Select one or more: a. Isotopic properties are the characteristics of polycrystalline materials. b. The crystal structure of metals is very complicated. c. Presence of various elements in the metallic crystal structures is the main contributor to its densely packed structure. d. Metal's crystalline structure tends to be densely packed. e. Anisotropic materials have their properties varying with the direction of measurement. f. The directional characteristic of metallic bonds is one of the reason for the densely packed crystalline structure of metals.

Answers

Answer:

c. Presence of various elements in the metallic crystal structures is the main contributor to its densely packed structure

d. Metal's crystalline structure tends to be densely packed.

e. Anisotropic materials have their properties varying with the direction of measurement.

Explanation:

a. Isotopic properties are the characteristics of polycrystalline materials.

False because crystalline solids are anisotropic in nature because some properties like refractive index change in different direction in crystalline solids .

b. The crystal structure of metals is very complicated

false - crystalline solids have fixed and ordered pattern. so it has simple structure .

c. false - there is only one element . packed structure is because of short bond length .

d.  true - metals are closely packed and in order manner

e.  true - they have different properties in all direction like electrical conductivity and refractive index

f.  False - metallic bonds are indirectional in nature .

When the following redox equation is balanced with smallest whole number coefficients, the coefficient for Sn(OH)3– will be _____. Bi(OH)3(s) + Sn(OH)3–(aq) → Sn(OH)62–(aq) + Bi(s) (basic solution)

Answers

Answer:

The coefficient of Sn(OH)_3^(-) is 3 in the balanced redox reaction.

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom loses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^(n+)+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^(n+)+ne^-\rightarrow X

For the given chemical reaction:

Bi(OH)_3+Sn(OH)_3^(-)\rightarrow Sn(OH)6^(2-)+Bi

The half cell reactions for the above reaction follows:

Oxidation half reaction:  Sn(OH)_3^(-)+3OH^-\rightarrow Sn(OH)6^(2-)+2e^-

Reduction half reaction:  Bi(OH)_3+3e^-\rightarrow Bi+3OH^-

To balance the oxidation half reaction must be multiplied by 3 and reduction half reaction must be multiplied by 2 thus, the balanced equation is:-

3Sn(OH)_3^(-)+3OH^-+2Bi(OH)_3\rightarrow 3Sn(OH)6^(2-)+2Bi

The coefficient of Sn(OH)_3^(-) is 3 in the balanced redox reaction.

What nuclide undergoes fission to form molybdenum-103, atomic number 42, tin-131, atomic number 50, and two neutrons? Element symbol: _______ mass number: _______

Answers

Answer:

The correct answer is Pu, 234.

Explanation:

In the given case, let us consider the reactant as X. Now the mass number (balanced) on both the sides will be,

Mass of X = Mass of Molybdenum + Mass of Tin + Mass of neutrons

M = 1 * 103 + 1 * 131 + 2 * 0

M = 234

Now the atomic number (balanced) on both the sides,

Atomic number of X = Atomic number of Molybdenum + Atomic number of Tin + Atomic number of neutrons

A = 1*42 + 1*50 + 2*1

A = 94

The atomic number 94 is for the element Plutonium, whose symbol is Pu. Thus, the reactant is 234-Pu.

Sulfonation of naphthalene, C10H8, results in two products. One product is kinetically favored and predominates in the beginning of the reaction. Because the reaction is reversible, eventually the kinetically slower but thermodynamically favored product predominates. Draw the structure of these two products. (The naphthalene ring is already drawn for you. Do not change the double bond configuration in the given structures.)

Answers

Explanation:

The sulfonation of the naphthalene yield 2 products under different conditions:

When the reaction is carried at 80 °C, 1-naphthalenesulfonic acid is the major product because it is kinetically favoured product as arenium ion formed in the transition state corresponding to 1-naphthalenesulfonic acid is more stable due to better resonance stabilization.

When the reaction is carried at 160 °C, 2-naphthalenesulfonic acid is the major product as it is more stable than 1-naphthalenesulfonic acid because of  steric interaction of the sulfonic acid group in 1-position and the hydrogen in 8-position.

The products are shown in image below.

How many moles of carbondioxide are produced when 0.2mol of sodium carbonate react with excess hydrovhloric acid

Answers

Answer:

0.2 moles of CO₂  are produced

Explanation:

Given data:

Moles of CO₂ produced = ?

Moles of Na₂CO₃ react = 0.2 mol

Solution:

Chemical equation:

Na₂CO₃ + 2HCl       →     2NaCl + CO₂ + H₂O

Now we will compare the moles of CO₂ with Na₂CO₃ .

                   Na₂CO₃          :             CO₂

                       1                  :               1

                    0.2                :             0.2

Thus, 0.2 moles of CO₂  are produced.